Solution 3:

(i) To determine ID and IR from the bias network;

ID = { VBB' - [ -VEE + VD(ON) ] } / RL1

= [ -3.457 + 4.5 - 0.8 ] / 1.3k

= 0.187 mA

IR = IE = [ VD(ON) - VBE(ECL) ] / RE2

= [ 0.8 - 0.75 ] / 0.15 = 0.333 mA

(ii) To determine the power dissipation;

PDiss = VEE ( ID + 2IR)

= 4.5 ( 0.187 + 2 x 0.333) = 3.8385 mW