Solution 2:

(i) To find the DC power dissipated :

VGS = 5 V

VOL = 0.6 V

Idd(OL) = K[(VGS - Vt) Vo - Vo^2/2]

= 50 [ (5 - 1) 0.6 - 0.6^2/2 ]

= 111 µA

The average power dissipated is therefore ;

PDD(avg) = [ IDD(OH) + IDD(OL) ] x Vdd/2

IDD(OH) = 0 -----------> No is cut-off at output high voltage

PDD(avg) = 111 x 5/2 = 277.5µW

(ii) The Dynamic power dissipated is ;

PDD(Dyn) = CL.f.(Vdd^2)

= 1.3 x 10^-12 x 10^6 x 5^2

= 32.5 µW

(iii) The total power dissipated ;

= 277.5 + 32.5 = 310 µW