Chapter - 19 : Solutions
Solution 4:
(i) To find VOH and VOL ;
VOH = Vdd - Vt,L = 5 -1 = 4 V
VOL = KL(Vdd - Vt,L)^2/ [ 2KL ( Vdd - Vt,L ) + 2Ko( Vdd - Vt,L - Vt,O)]
= (20/3)(5 - 1)^2 / [ (2x20/3)(5 - 1) + 80 (5 - 1 - 1)] = 0.364 V
(ii) To find VIH and Vo(IH) ;
VIH = Vt,O + 2(Vdd - Vt,L)
Sqrt( 3Ko/KL) + 1
= 1 + {8/ [Sqrt ( 18 ) + 1]} = 2.526 V
Vo(IH) = {Ko( VIH - Vt,O) + KL( Vdd - Vt,L)} / (2Ko + KL)
= {40 ( 2.526 - 1 ) + (20/3)(5 - 1)} / ( 80 + (20/3))
= 1.012V
(iii) To find VM ;
VM = Vdd - Vt,L + Sqrt( Ko/KL ) x Vt,O
1 + Sqrt ( Ko / KL )
= 5 - 1 + Sqrt ( 6 ) x 1 = 1.87 V
1 + Sqrt ( 6 )
(iv) To find VIL and Vo(IL) ;
VIL = Vt,O = 1 V
Vo(IL) = Vdd - Vt,L = 5 - 1 = 4V
Voltage transfer Characteristics