Id(lin) = 5[(Vgs - 1)Vds - Vds^2 / 2]
We know that,
Id(lin) = K [(Vgs - Vt)Vds - Vds^2 / 2]
Hence K= 5 ; Vt = 1v
We also know that,
Vds = Vgs - Vt
Given, Vgs = 2v, 3v, 4v, 5v, and 6v.
Hence, Vds = 1v, 2v, 3v, 4, and 5v respectively.
By using the expression for Id(lin), we can find Id(lin) to be 2.5mA, 10mA, 22.5mA, 40mA, and 62.5mA.
Hence, we can sketch the Id Vs Vds curve as follows :
