Solution 2:
Id(lin) = 4 [(Vgs + 2)Vds - Vds^2 / 2]
We know that,
Id(lin) = K {(Vgs - Vt)Vds - Vds^2 / 2]
Hence, K= 4 ; Vt = -2v
We also know that,
Vds = Vgs - Vt
Given, Vgs = 0v, 1v, 2v, 3v, and 4v.
Hence, Vds = 2v, 3v, 4v, 5v, and 6v respectively.
By using the current expression, we can find Id(lin) to be 8mA, 18mA, 32mA, 50mA, and 72mA.
Hence we can sketch the Id Vs Vds curve as follows :